Calculate the average atomic mass of chlorine using the following data:
Isotope Natural abundance (%) Molar mass $(u)$ $^{35}Cl$ $75.77$ $34.9689$ $^{37}Cl$ $24.23$ $36.9659$
(in $u$)
| Isotope | Natural abundance (%) | Molar mass $(u)$ |
|---|---|---|
| $^{35}Cl$ | $75.77$ | $34.9689$ |
| $^{37}Cl$ | $24.23$ | $36.9659$ |
- A$35.4527$
- B$36.4527$
- C$34.4527$
- D$35.9659$
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